思路：倒序单调栈。弹出所有 ≤ 当前身高的元素（这些人都能被看到），count 为弹出数量；若栈非空，还能看到栈顶（第一个更高的人），故 +1。能看到的人数 = count + (栈非空 ? 1 : 0)。
Do you need to respond to every message? There’s often someone who feels the need to type out a reply to every post, even if it’s just to say “thanks.” But doing so in a big group might be somewhat akin to an email reply-all storm.。服务器推荐对此有专业解读
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Perplexity has introduced "Computer," a new tool that allows users to assign tasks and see them carried out by a system that coordinates multiple agents running various models.，推荐阅读heLLoword翻译官方下载获取更多信息
Андрей Шеньшаков
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